misc2
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misc2 [2013/12/06 16:37] – potthast | misc2 [2013/12/06 16:41] – potthast | ||
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//Remark.// A reordering operation is equivalent to the application of a permutation | //Remark.// A reordering operation is equivalent to the application of a permutation | ||
- | matrix $P$. | + | matrix $P$, i.e. a matrix which has exactly one element 1 in each row and column, with |
+ | all other elements zero. | ||
//Proof.// We first assume that in the state space $X = \mathbb{R}^n$ each element belong | //Proof.// We first assume that in the state space $X = \mathbb{R}^n$ each element belong | ||
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is influenced by the entries in the $\ell$-th row of the matrix $H$. Thus, this is local | is influenced by the entries in the $\ell$-th row of the matrix $H$. Thus, this is local | ||
if and only if at most one of the entries is non-zero. This applies to every row, i.e. in | if and only if at most one of the entries is non-zero. This applies to every row, i.e. in | ||
- | each row there is at most one non-zero element. | + | each row there is at most one non-zero element. |
- | + | are influenced by different points, this means that there can be at most one nonzero entry | |
- | $\Box$ \\ | + | in each column as well. But that means that the operator $H$ looks like a scaled version of |
+ | a permutation matrix $P$, with scaling $0$ allowed. Clearly, by reordering we can make this | ||
+ | into a diagonal matrix, and the proof is complete | ||
misc2.txt · Last modified: 2023/03/28 09:14 by 127.0.0.1