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misc2 [2013/12/06 16:39] potthastmisc2 [2013/12/06 16:41] potthast
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 //Remark.// A reordering operation is equivalent to the application of a permutation  //Remark.// A reordering operation is equivalent to the application of a permutation 
-matrix $P$. +matrix $P$, i.e. a matrix which has exactly one element 1 in each row and column, with  
 +all other elements zero
  
 //Proof.// We first assume that in the state space $X = \mathbb{R}^n$ each element belong //Proof.// We first assume that in the state space $X = \mathbb{R}^n$ each element belong
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 are influenced by different points, this means that there can be at most one nonzero entry are influenced by different points, this means that there can be at most one nonzero entry
 in each column as well. But that means that the operator $H$ looks like a scaled version of  in each column as well. But that means that the operator $H$ looks like a scaled version of 
-a permutation matrix $P$, with scaling $0$ allowed.  +a permutation matrix $P$, with scaling $0$ allowed. Clearly, by reordering we can make this 
- +into a diagonal matrix, and the proof is complete $\Box$ \\
-$\Box$ \\+
  
  
misc2.txt · Last modified: 2023/03/28 09:14 by 127.0.0.1